Antipode of Panbang, Bhutan
The opposite side of the world to Panbang is San Juan Bautista, Valparaiso, Chile.
Panbang
Bhutan
Continent: Asia
Coordinates: 26.867, 90.983
Antipodal point
South Pacific Ocean
Exact location on the other side of the world
Coordinates: -26.867, -89.017
San Juan Bautista
Chile
San Juan Bautista is the closest city to Panbang's antipodal point (1,233 km).
The antipodal city to Panbang is San Juan Bautista. This means that, among all the populated locations in the world, the farthest city from Panbang is San Juan Bautista.
The distance from Panbang to San Juan Bautista is about 19,000 kilometers. A direct flight would take around 21 hours, but there aren't commercial routes between these cities.
Cities on the other side of the world of Panbang
This table contains the populated locations that are closest to Panbang's antipode. These are the farthest cities in the world from Panbang.
| City | Country | Distance from antipode | Coordinates |
|---|---|---|---|
| San Juan Bautista, Valparaiso | Chile | 1,233 km | (-33.637, -78.834) |
| Huasco, Atacama | Chile | 1,763 km | (-28.466, -71.223) |
| Coquimbo, Coquimbo Region | Chile | 1,764 km | (-29.953, -71.339) |
| La Serena, Coquimbo Region | Chile | 1,772 km | (-29.906, -71.250) |
| La Higuera, Coquimbo Region | Chile | 1,772 km | (-29.512, -71.202) |
| Huentelauquén, Coquimbo Region | Chile | 1,776 km | (-31.584, -71.534) |
| Freirina, Atacama | Chile | 1,777 km | (-28.509, -71.081) |
| Punitaqui, Coquimbo Region | Chile | 1,786 km | (-30.834, -71.259) |
| Ovalle, Coquimbo Region | Chile | 1,787 km | (-30.601, -71.199) |
| Los Vilos, Coquimbo Region | Chile | 1,787 km | (-31.913, -71.500) |
Local time:
Time Zone: Asia/Thimphu
Coordinates: 26.8667° N 90.9833° E
Elevation: 214 m (702 ft)
Local time:
Time Zone: America/Santiago
Coordinates: 33.6371° S 78.8337° W
Elevation: 62 m (203 ft)
How to calculate the antipodal point?
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
- LatO: Latitude at the origin point.
- LngO: Longitude at the origin point.
- LatA: Latitude at the antipodal point.
- LngA: Longitude at the antipodal point.
Step 1: Obtain the geographic coordinates of Panbang
The DMS coordinates are: 26°52'0'' N 90°58'60'' E .
Calculations are easier by using the decimal format, hence:
LatO = 26.86667°
LngO = 90.98333°
Step 2: Calculate the latitude
LatA = - LatO = -26.86667°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 90.98333 - 180° = -89.01667°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Panbang is located on coordinates: (LatA, LngA) = (-26.86667, -89.01667)
In DMS format: 26°52'0'' N 90°58'60'' E .