Antipode of Panbang, Bhutan

The opposite side of the world to Panbang is Coquimbo, Coquimbo Region, Chile.

Panbang

Bhutan

Continent: Asia

Coordinates: 26.867, 90.983

Antipodal point

Opposite side in the world

Continent: Asia

Coordinates: -26.867, -89.017

Coquimbo

Chile

Coquimbo is the closest city to Panbang's antipodal point (1,764 km).

The antipodal city to Panbang is Coquimbo. This means that, among all the populated locations in the world, the farthest city from Panbang is Coquimbo.

The distance from Panbang to Coquimbo is about 18,000 kilometers. A direct flight would take around 20 hours, but there aren't commercial routes between these cities.

Cities on the other side of the world of Panbang

This table contains the populated locations that are closest to Panbang's antipode. These are the farthest cities in the world from Panbang.

City Country Distance from antipode Coordinates
Coquimbo, Coquimbo Region Chile 1,764 km (-29.953, -71.339)
La Serena, Coquimbo Region Chile 1,772 km (-29.905, -71.249)
Ovalle, Coquimbo Region Chile 1,787 km (-30.601, -71.199)
Vallenar, Atacama Chile 1,809 km (-28.576, -70.759)
Valparaíso Chile 1,809 km (-33.036, -71.630)
Illapel, Coquimbo Region Chile 1,811 km (-31.633, -71.170)
Monte Patria, Coquimbo Region Chile 1,811 km (-30.695, -70.958)
Viña del Mar, Valparaíso Chile 1,816 km (-33.025, -71.552)
El Tabo, Valparaíso Chile 1,821 km (-33.450, -71.667)
Vicuña, Coquimbo Region Chile 1,825 km (-30.035, -70.713)

Panbang, Bhutan

Local time:

Coordinates: 26.8667° N 90.9833° E

Coquimbo, Chile

Local time:

Coordinates: 29.9533° S 71.3395° W

How to calculate the antipodal point?

The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:

  • LatO: Latitude at the origin point.
  • LngO: Longitude at the origin point.
  • LatA: Latitude at the antipodal point.
  • LngA: Longitude at the antipodal point.

Step 1: Obtain the geographic coordinates of Panbang

The DMS coordinates are: 26°52'0'' N 90°58'60'' E .

Calculations are easier by using the decimal format, hence:

LatO = 26.86667°

LngO = 90.98333°

Step 2: Calculate the latitude

LatA = - LatO = -26.86667°

Since the latitude is positive (north direction), the antipode must be negative (south direction).

Step 3: Calculate the longitude

LngA = LngO ± 180° = 90.98333 - 180° = -89.01667°

Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.

Result:

The antipode of Panbang is located on coordinates: (LatA, LngA) = (-26.86667, -89.01667)

In DMS format: 26°52'0'' N 90°58'60'' E .

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