The opposite side of the world to San Pablo de Tiquina is Hoàng Sa, Vietnam.
Bolivia
Continent: South America
Coordinates: -16.218, -68.843
South China Sea
Exact location on the other side of the world
Coordinates: 16.218, 111.157
Vietnam
Hoàng Sa is the closest city to San Pablo de Tiquina's antipodal point (143 km).
The antipodal city to San Pablo de Tiquina is Hoàng Sa. This means that, among all the populated locations in the world, the farthest city from San Pablo de Tiquina is Hoàng Sa.
The distance from San Pablo de Tiquina to Hoàng Sa is about 20,000 kilometers. A direct flight would take around 22 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to San Pablo de Tiquina's antipode. These are the farthest cities in the world from San Pablo de Tiquina.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Hoàng Sa | Vietnam | 143 km | (16.835, 112.339) |
Sansha, Hainan | China | 144 km | (16.839, 112.341) |
Hoàng Sa, Da Nang | Vietnam | 175 km | (16.667, 112.725) |
Lý Sơn, Quảng Ngãi Province | Vietnam | 238 km | (15.372, 109.119) |
Li’an, Hainan | China | 271 km | (18.433, 110.067) |
Xincun, Hainan | China | 274 km | (18.416, 109.964) |
Bình Sơn, Quảng Ngãi Province | Vietnam | 276 km | (15.298, 108.761) |
Sơn Tịnh, Quảng Ngãi Province | Vietnam | 279 km | (15.159, 108.796) |
Tư Nghĩa, Quảng Ngãi Province | Vietnam | 280 km | (15.085, 108.826) |
Mộ Đức, Quảng Ngãi Province | Vietnam | 281 km | (14.955, 108.886) |
Local time:
Time Zone: America/La_Paz
Coordinates: 16.218° S 68.8428° W
Elevation: 3,823 m (12,543 ft)
Local time:
Time Zone: Asia/Shanghai
Coordinates: 16.8352° N 112.3387° E
Elevation: 13 m (43 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of San Pablo de Tiquina
The DMS coordinates are: 16°13'4.6'' S 68°50'34.1'' W.
Calculations are easier by using the decimal format, hence:
LatO = -16.21795°
LngO = -68.8428°
Step 2: Calculate the latitude
LatA = - LatO = 16.21795°
Since the latitude is negative (south direction), the antipode must be positive (north direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = -68.8428 + 180° = 111.1572°
Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.
Result:
The antipode of San Pablo de Tiquina is located on coordinates: (LatA, LngA) = (16.21795, 111.1572)
In DMS format: 16°13'4.6'' S 68°50'34.1'' W.