Antipode of San Cristobal, Cuba

The opposite side of the world to San Cristobal is West Island, Cocos Islands.

San Cristobal

Cuba

Continent: America

Coordinates: 22.717, -83.056

Antipodal point

Opposite side in the world

Continent: America

Coordinates: -22.717, 96.944

West Island

Cocos Islands

West Island is the closest city to San Cristobal's antipodal point (1,169 km).

The antipodal city to San Cristobal is West Island. This means that, among all the populated locations in the world, the farthest city from San Cristobal is West Island.

The distance from San Cristobal to West Island is about 19,000 kilometers. A direct flight would take around 21 hours, but there aren't commercial routes between these cities.

Cities on the other side of the world of San Cristobal

This table contains the populated locations that are closest to San Cristobal's antipode. These are the farthest cities in the world from San Cristobal.

City Country Distance from antipode Coordinates
West Island Cocos Islands 1,169 km (-12.157, 96.823)
Flying Fish Cove Christmas Island 1,648 km (-10.422, 105.679)
Brockman, WA Australia 1,719 km (-24.881, 113.654)
Carnarvon, WA Australia 1,719 km (-24.883, 113.657)
Morgantown, WA Australia 1,719 km (-24.877, 113.659)
South Carnarvon, WA Australia 1,719 km (-24.893, 113.658)
Denham, WA Australia 1,720 km (-25.927, 113.533)
East Carnarvon, WA Australia 1,721 km (-24.864, 113.678)
Kingsford, WA Australia 1,723 km (-24.864, 113.695)
Coral Bay, WA Australia 1,726 km (-23.141, 113.776)

San Cristobal, Cuba

Local time:

Coordinates: 22.7166° N 83.0565° W

West Island, Cocos Islands

Local time:

Coordinates: 12.1568° S 96.8225° E

How to calculate the antipodal point?

The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:

  • LatO: Latitude at the origin point.
  • LngO: Longitude at the origin point.
  • LatA: Latitude at the antipodal point.
  • LngA: Longitude at the antipodal point.

Step 1: Obtain the geographic coordinates of San Cristobal

The DMS coordinates are: 22°42'59.7'' N 83°3'23.3'' W.

Calculations are easier by using the decimal format, hence:

LatO = 22.71658°

LngO = -83.05647°

Step 2: Calculate the latitude

LatA = - LatO = -22.71658°

Since the latitude is positive (north direction), the antipode must be negative (south direction).

Step 3: Calculate the longitude

LngA = LngO ± 180° = -83.05647 + 180° = 96.94353°

Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.

Result:

The antipode of San Cristobal is located on coordinates: (LatA, LngA) = (-22.71658, 96.94353)

In DMS format: 22°42'59.7'' N 83°3'23.3'' W.

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