The opposite side of the world to Pakxan is Puerto de Lomas, Arequipa, Peru.
Laos
Continent: Asia
Coordinates: 18.394, 103.661
South Pacific Ocean
Exact location on the other side of the world
Coordinates: -18.394, -76.339
Peru
Puerto de Lomas is the closest city to Pakxan' antipodal point (351 km).
The antipodal city to Pakxan is Puerto de Lomas. This means that, among all the populated locations in the world, the farthest city from Pakxan is Puerto de Lomas.
The distance from Pakxan to Puerto de Lomas is about 20,000 kilometers. A direct flight would take around 22 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Pakxan's antipode. These are the farthest cities in the world from Pakxan.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Puerto de Lomas, Arequipa | Peru | 351 km | (-15.569, -74.850) |
Atiquipa, Arequipa | Peru | 356 km | (-15.796, -74.364) |
Chala, Arequipa | Peru | 358 km | (-15.866, -74.247) |
San Juan, Ica | Peru | 358 km | (-15.365, -75.162) |
Yauca, Arequipa | Peru | 359 km | (-15.661, -74.527) |
Bella Unión, Arequipa | Peru | 372 km | (-15.450, -74.658) |
Atico, Arequipa | Peru | 377 km | (-16.209, -73.622) |
Minas de Marcona, Ica | Peru | 376 km | (-15.212, -75.110) |
Acarí, Arequipa | Peru | 377 km | (-15.424, -74.614) |
Jaquí, Arequipa | Peru | 381 km | (-15.477, -74.442) |
Local time:
Time Zone: Asia/Vientiane
Coordinates: 18.3942° N 103.6611° E
Elevation: 156 m (512 ft)
Local time:
Time Zone: America/Lima
Coordinates: 15.5689° S 74.8503° W
Elevation: 19 m (62 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Pakxan
The DMS coordinates are: 18°23'39.1'' N 103°39'40'' E .
Calculations are easier by using the decimal format, hence:
LatO = 18.3942°
LngO = 103.6611°
Step 2: Calculate the latitude
LatA = - LatO = -18.3942°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 103.6611 - 180° = -76.3389°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Pakxan is located on coordinates: (LatA, LngA) = (-18.3942, -76.3389)
In DMS format: 18°23'39.1'' N 103°39'40'' E .