Antipode of Pakxong, Laos
The opposite side of the world to Pakxong is Pullo, Ayacucho, Peru.
Pakxong
Laos
Continent: Asia
Coordinates: 15.182, 106.230
Antipodal point
Opposite side in the world
Continent: Asia
Coordinates: -15.182, -73.770
Pullo
Peru
Pullo is the closest city to Pakxong's antipodal point (7 km).
The antipodal city to Pakxong is Pullo. This means that, among all the populated locations in the world, the farthest city from Pakxong is Pullo.
The distance from Pakxong to Pullo is about 20,000 kilometers. A direct flight would take around 22 hours, but there aren't commercial routes between these cities.
Cities on the other side of the world of Pakxong
This table contains the populated locations that are closest to Pakxong's antipode. These are the farthest cities in the world from Pakxong.
| City | Country | Distance from antipode | Coordinates |
|---|---|---|---|
| Pullo, Ayacucho | Peru | 7 km | (-15.209, -73.830) |
| Chumpi, Ayacucho | Peru | 9 km | (-15.100, -73.767) |
| Coracora, Ayacucho | Peru | 16 km | (-15.033, -73.783) |
| Incuyo, Ayacucho | Peru | 23 km | (-15.249, -73.571) |
| Chaviña, Ayacucho | Peru | 23 km | (-14.983, -73.833) |
| Sancos, Ayacucho | Peru | 24 km | (-15.063, -73.952) |
| Quilcata, Ayacucho | Peru | 35 km | (-15.246, -73.451) |
| Lampa, Ayacucho | Peru | 45 km | (-15.184, -73.349) |
| Tambo, Ayacucho | Peru | 46 km | (-14.798, -73.924) |
| Marcabamba, Ayacucho | Peru | 46 km | (-15.151, -73.342) |
Pakxong, Laos
Local time:
Coordinates: 15.1815° N 106.2304° E
Pullo, Peru
Local time:
Coordinates: 15.2094° S 73.8297° W
How to calculate the antipodal point?
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
- LatO: Latitude at the origin point.
- LngO: Longitude at the origin point.
- LatA: Latitude at the antipodal point.
- LngA: Longitude at the antipodal point.
Step 1: Obtain the geographic coordinates of Pakxong
The DMS coordinates are: 15°10'53.5'' N 106°13'49.4'' E .
Calculations are easier by using the decimal format, hence:
LatO = 15.18154°
LngO = 106.23038°
Step 2: Calculate the latitude
LatA = - LatO = -15.18154°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 106.23038 - 180° = -73.76962°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Pakxong is located on coordinates: (LatA, LngA) = (-15.18154, -73.76962)
In DMS format: 15°10'53.5'' N 106°13'49.4'' E .
