The opposite side of the world to Xochimilco is Seabreeze village, British Indian Ocean Territory.
Mexico
Continent: America
Coordinates: 19.255, -99.104
Indian Ocean
Exact location on the other side of the world
Coordinates: -19.255, 80.896
British Indian Ocean Territory
Seabreeze village is the closest city to Xochimilco's antipodal point (1,613 km).
The antipodal city to Xochimilco is Seabreeze village. This means that, among all the populated locations in the world, the farthest city from Xochimilco is Seabreeze village.
The distance from Xochimilco to Seabreeze village is about 18,000 kilometers. A direct flight would take around 20 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Xochimilco's antipode. These are the farthest cities in the world from Xochimilco.
| City | Country | Distance from antipode | Coordinates |
|---|---|---|---|
| Seabreeze village | British Indian Ocean Territory | 1,613 km | (-7.287, 72.381) |
| Downtown | British Indian Ocean Territory | 1,615 km | (-7.262, 72.377) |
| Port Mathurin, Rodrigues | Mauritius | 1,835 km | (-19.683, 63.417) |
| Baie aux Huîtres, Rodrigues | Mauritius | 1,836 km | (-19.694, 63.408) |
| West Island | Cocos Islands | 1,878 km | (-12.157, 96.823) |
| Meedhoo, Seenu | Maldives | 2,228 km | (-0.583, 73.233) |
| Hithadhoo, Seenu | Maldives | 2,233 km | (-0.600, 73.083) |
| Fuvahmulah, Gnyaviyani Atoll | Maldives | 2,250 km | (-0.299, 73.424) |
| Cargados Carajos | Mauritius | 2,268 km | (-16.603, 59.659) |
| Gadhdhoo, Gaafu Dhaalu Atoll | Maldives | 2,310 km | (0.290, 73.457) |
Local time:
Time Zone: America/Mexico_City
Coordinates: 19.2547° N 99.1036° W
Elevation: 2,244 m (7,362 ft)
Local time:
Time Zone: Indian/Chagos
Coordinates: 7.2875° S 72.3809° E
Elevation: 1 m (3 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Xochimilco
The DMS coordinates are: 19°15'16.7'' N 99°6'12.8'' W.
Calculations are easier by using the decimal format, hence:
LatO = 19.25465°
LngO = -99.10356°
Step 2: Calculate the latitude
LatA = - LatO = -19.25465°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = -99.10356 + 180° = 80.89644°
Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.
Result:
The antipode of Xochimilco is located on coordinates: (LatA, LngA) = (-19.25465, 80.89644)
In DMS format: 19°15'16.7'' N 99°6'12.8'' W.