Acapulco de Juárez is located at latitude 16.84942 and longitude -99.90891. It is part of America and the northern hemisphere.
16.8494° N 99.9089° W
16°50'57.9'' N 99°54.535' W
The geographic coordinate system enables any place in the world to be located using its latitude and longitude. The latitude is the position relative to the equator, specifying the north-south position. The longitude specifies the east-west position measured from a reference meridian (usually the Greenwich Prime Meridian). The latitude and longitude of Acapulco de Juárez have been calculated based on the geodetic datum WGS84.
There are many systems and formats to represent geographic coordinates. The following table matches the equivalence between the most common formats:
|Simple decimal standard||16.84942||-99.90891|
|Decimal Degrees (DD)||16.8494° N||99.9089° W|
|Degrees and Decimal Minutes (DDM)||16°50.965' N||99°54.535' W|
|Degrees, Minutes and Seconds (DMS)||16°50'57.9'' N||99°54'32.1'' W|
|Yangon, Myanmar||16.80528, 96.15611|
|Tuxtla, Mexico||16.75973, -93.11308|
|San Cristobal, Mexico||16.73176, -92.64126|
|Salina Cruz, Mexico||16.17535, -95.19424|
|Vijayawada, India||16.50745, 80.6466|