The opposite side of the world to Cagayan de Oro is Castelo dos Sonhos, Pará, Brazil.
Philippines
Continent: Asia
Coordinates: 8.482, 124.647
Brazil
Continent: South America
Coordinates: -8.482, -55.353
Brazil
Castelo dos Sonhos is the closest city to Cagayan de Oro' antipodal point (33 km).
The antipodal city to Cagayan de Oro is Castelo dos Sonhos. This means that, among all the populated locations in the world, the farthest city from Cagayan de Oro is Castelo dos Sonhos.
The distance from Cagayan de Oro to Castelo dos Sonhos is about 20,000 kilometers. A direct flight would take around 22 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Cagayan de Oro's antipode. These are the farthest cities in the world from Cagayan de Oro.
| City | Country | Distance from antipode | Coordinates |
|---|---|---|---|
| Castelo dos Sonhos, PA | Brazil | 33 km | (-8.317, -55.100) |
| Novo Progresso, PA | Brazil | 160 km | (-7.041, -55.420) |
| Novo Mundo, MT | Brazil | 166 km | (-9.976, -55.178) |
| Guarantã do Norte, MT | Brazil | 170 km | (-9.951, -54.908) |
| Carlinda, MT | Brazil | 172 km | (-9.958, -55.832) |
| Alta Floresta, MT | Brazil | 174 km | (-9.876, -56.086) |
| Paranaíta, MT | Brazil | 180 km | (-9.665, -56.477) |
| Matupá, MT | Brazil | 192 km | (-10.169, -54.934) |
| Peixoto de Azevedo, MT | Brazil | 199 km | (-10.244, -54.992) |
| Nova Guarita, MT | Brazil | 203 km | (-10.313, -55.408) |
Local time:
Time Zone: Asia/Manila
Coordinates: 8.4822° N 124.6472° E
Elevation: 8 m (26 ft)
Local time:
Time Zone: America/Santarem
Coordinates: 8.3168° S 55.1° W
Elevation: 384 m (1,260 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Cagayan de Oro
The DMS coordinates are: 8°28'56'' N 124°38'50'' E .
Calculations are easier by using the decimal format, hence:
LatO = 8.48222°
LngO = 124.64722°
Step 2: Calculate the latitude
LatA = - LatO = -8.48222°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 124.64722 - 180° = -55.35278°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Cagayan de Oro is located on coordinates: (LatA, LngA) = (-8.48222, -55.35278)
In DMS format: 8°28'56'' N 124°38'50'' E .